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olga nikolaevna [1]
3 years ago
6

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 45.0 and 55.

0 minutes. Find the probability that a given class period runs between 50.25 and 50.5 minutes.
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0

Answer: 0.025

Step-by-step explanation:

The probability density function for a random variable that is uniformly distributed on interval [a,b] is given by :-

f(x)=\dfrac{1}{b-a}

Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 45.0 and 55.0 minutes.

Let x be the random variable that denotes the  lengths of her classes.

Then, the probability density function = f(x)=\dfrac{1}{55-45}=\dfrac{1}{10}

Now, the probability that a given class period runs between 50.25 and 50.5 minutes will be :-

P(50.25

Hence, the required probability =0.025

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Answer and Step-by-step explanation:

Hello~let's~solve~your~equation:

<u>Step 1: Simplify both sides of the equation:</u>

(\frac{4}{5}) (x)+(\frac{4}{5})(\frac{5}{6})+\frac{-2}{3}x+\frac{1}{6}    =\frac{7}{6}  (Distribute)

\frac{4}{5}x+\frac{2}{3}+\frac{-2}{3}x+\frac{1}{y\6}=\frac{7}{6}

(\frac{5}{5}x+ \frac{-2}{3}x )+(\frac{2}{3}+ \frac{1}{6})=\frac{7}{6} (Combine~like~terms)

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<u>Step 2: Subtract 5/6 from both sides:</u>

\frac{2}{15}x+\frac{5}{6}- \frac{5}{6} =\frac{7}{6} -\frac{5}{6}

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x= \frac{5}{2}

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Answer:

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Step-by-step explanation:

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\left[\begin{array}{cc}7&-4\\10&-6\\\end{array}\right] \left[\begin{array}{c}x&y\\\\\end{array}\right] = \right] \left[\begin{array}{c}4&2\\\\\end{array}\right]

first we will find the determinant of the matrix A

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To get the value of x, we will substitute the column matrix at the right hand side to replace the first column pf matrix A, then we look for the determinant and divide the determinant by the determinant of matrix A itself.

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