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Svetradugi [14.3K]

3 years ago

6

13/100 + 11/10 helpppp

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer:

13/100 + 11/10 = 123/100

Step-by-step explanation:

user100 [1]3 years ago

3 0

Answer:

123/100

Step-by-step explanation:

make them both go into 100

13/100 = 13/100

11/10 = 11 $11*10 = 11010*10 +100\\110/100$

add 13/100 to 110/100

you get 123/100 or 1.23

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Make a box and whisker plot of the data.<br><br> 24, 18, 29, 21, 16, 23, 13, 11

Elanso [62]

To make a box and whisker plot you must first order the data:

11, 13, 16, 18, 21, 23, 24, 29

Then find the median:

19.5

Then split the data into two sections by the median:

11, 13, 16, 18 and 21, 23, 24, 29

Now find the medians of those sets

14.5 and 23.5

With this information we can conclude Option C is the correct plot

Hope this helps!

7 0

3 years ago

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Determine the value of x to the nearest thousandth in the equation 8(2)^x+3=48

solong [7]

You probably mean either

$8\cdot2^x + 3 = 48$

or

$8\cdot2^{x+3} = 48$

Write 8 = 2³, so that in the first interpretation,

$8\cdot2^x = 2^3 \cdot 2^x = 2^{x + 3}$

and in the second,

$8\cdot2^{x+3} = 2^3 \cdot 2^{x+3} = 2^{x + 6}$

Then in the first interpretation, we have

$2^{x + 3} + 3 = 48 \implies 2^{x + 3} = 45 \implies x + 3 = \log_2(45) \implies x = \log_2(45) - 3 \approx \boxed{2.492}$

Otherwise, the second interpretation gives

$2^{x + 6} = 48 \implies x + 6 = \log_2(48) \implies x = \log_2(48) - 6 \approx -0.415$

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2 years ago

A square field has an area of 10 square miles. What is the approximate length, to the nearest thousandth, of one side of this fi

blsea [12.9K]

$A=10 [mi^{2}]\\
A=s*s=s^{2}\\
s= \sqrt{A} \\
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3 years ago

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I need help please !

Harman [31]

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4 0

3 years ago

Find the distance between the points (-3, 11) and (5,5).<br> O 10<br> 2/10<br> o 2.17

german

Answer: d = 10

Step-by-step explanation:

Step-by-step explanation:

The formula for calculating distance between two points is given by :

d = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

$x_{1}$ = -3

$x_{2}$ = 5

$y_{1}$ = 11

$y_{2}$ = 5

substituting the values , we have

d = $\sqrt{(5-(-3))^{2}+(5-11)^{2}}$

d = $\sqrt{(5+3)^{2}+(-6)^{2}}$

d = $\sqrt{(8)^{2}+(-6)^{2}}$

d = $\sqrt{64+36}$

d = $\sqrt{100}$

d = 10

4 0

3 years ago

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