Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer:
415.63 minutes
Step-by-step explanation:
Growth can be represented by the equation 
. We can find the rate at which it grows by using t=25 minutes and 
or double the amount at that time. The first step we always take is to divide 
by A.
![[tex]\frac{A_{0}}{A}=e^{rt}\\2=e^{r(25)}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7BA_%7B0%7D%7D%7BA%7D%3De%5E%7Brt%7D%5C%5C2%3De%5E%7Br%2825%29%7D)
To solve for r, we will take the natural log of both sides and use log rules to isolate r.
We know 
so we were able to cancel it out and divide both sides by 25.
We solve with a calculator 
We change 0.0277 into a percent by multiplying by 100 to get 2.77% as the rate.
The equation is 
.
We repeat the step above substituting A=5,000,000, =50, and r=0.02777. Then solve for t.
t=415.63 minutes
Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
