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navik [9.2K]
3 years ago
10

What is the proof for this?

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0
Knowing nexnjhdjhdhfgnu. Hngj
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SMART STUDENT PLEASE NEED GOOD MATH STUDENT​
tangare [24]

Answer:

Therefore 'x' is equal to 65.4°

Step-by-step explanation:

In Right Angle Triangle ABC

∠ B = 90°

AC = Hypotenuse = 12

CB = Adjacent Side = 5

To Find:

∠ C = x

Solution:

In Right Angle Triangle ABC Cosine Identity we have

\cos C = \frac{\textrm{side adjacent to angle C}}{Hypotenuse}\\

Substituting the values we get

\cos C = \dfrac{CB}{AC}=\dfrac{5}{12}

\angle C = \cos^{-1}(0.4166)=65.37=65.4\°

Therefore 'x' is equal to 65.4°

8 0
3 years ago
According to the property √a/√b=√a/b, which choice is equivalent to the quotient below? √35/√7​
Ilya [14]

Answer:

D

Step-by-step explanation:

\frac{\sqrt{35} }{\sqrt{7} } =\frac{\sqrt{5} \times \sqrt{7} }{\sqrt{7} } =\sqrt{5}

4 0
3 years ago
find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
katrin2010 [14]

A generic odd number can be written as

2k+1,\quad k \in \mathbb{Z}

Since there is an odd number every two numbers, three consecutive odd numbers will be

2k+1,\quad 2k+3,\quad 2k+5

Now let's make up the equations: the sum of the first two is

(2k+1)+(2k+3)

And 27 less than 3 times the largest is

3(2k+5)-27

These two must be the same, so we have

(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3

Subtracting 4k and 3 from both sides gives

1=2k \iff k=\dfrac{1}{2}

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0
3 years ago
Find the nth term of this sequence, 3, 6, 9, 12
miss Akunina [59]

Answer:

\large\boxed{\sf n^{th} \ term =3n}}

Step-by-step explanation:

Find common difference from subtracting any term in the sequence with the previous term.

\large{\sf 6-3}=3

Apply nth term formula.

\large{\sf a_n=a_1+(n-1)d

\large{\sf d=3 \ \ a_1=3}

\large{\sf a_n=3+(n-1)3

\large{\sf a_n=3+3n-3

\large{\sf a_n=3n}

3 0
3 years ago
Read 2 more answers
50 POINTS please show the step by step process.I already know the answers i just the steps!!
djyliett [7]

Answer: 8x

2.9543127e+21xy

9x

Step-by-step explanation:

4x^2=16x     28x=28x     36=36      16x+28x-36   16+28=44-36=8x

125x^6= 30517578125x    27y^15= 2.9543127e+21                             30517578125x-2.9543127e+21= 2.9543127e+21xy

4-7=3+x=3x    5-8=3+x=3x   3x * 3x= 9x

7 0
3 years ago
Read 2 more answers
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