All categories

3 years ago

I need the answer to 7 please

Mathematics

2 answers:

bija089 [108]3 years ago

6 0

7. a

Given,

Diameter = 16 feet

So, radius = 16 feet/2 = 8 feet

Circumference = 2πr

So, circumference of this circle

= 2πr

= 2 × 3.14 × 8 feet

= 3.14 × 16 feet

= 50.24 feet

Given,

Diameter = 16 feet

So, radius = 16 feet/2 = 8 feet

Area = πr²

So, area of this circle

= 3.14 × (8 feet)²

= 3.14 × 64 feet²

= 200.96 feet²

horrorfan [7]3 years ago

5 0

Answer:

Done

Step-by-step explanation:

Area - 201.06192983

Circumference - 50.2654824574

You might be interested in

Part2 of the math homework

Molodets [167]

Option four is the answer bc 8^2 is 64 and so is 4^3. so for the answer to be correct, it should say = and not ≠

5 0

3 years ago

Multiply 4(x+6)/(x−2)⋅(x+10)/24(x+6)

liq [111]

Answer:

Step-by-step explanation:

4(x+6)/(x-2)*(x+10)/24(x+6)

First we do 4(x+6)

4x+24

Then we do 24(x+6)

24x+144

So we plug it in

4x+24/x-2*x+10/24x+144

5 0

3 years ago

Help on this This question plz

mr Goodwill [35]

= -x^2 - (3x - 12x^2 + 7x ) - (2 - 2x - 2)
= -x^2 - 3x + 12x^2 - 7x - 2 + 2x + 2
= 11x^2 - 8x

Answer
11x^2 - 8x

6 0

3 years ago

Mr. Smith estimates that

OLEGan [10]

Answer:

B. 7.5 hours

Step-by-step explanation:

Assuming that both hoses fill at the same rate, then by simple proportion,

To raise the pool by 1 foot of water:

1 hose ---> takes 3 hours

2 hoses ----> fills twice as fast ---> will take half the time ---> 3/2 = 1.5 hrs

Hence with 2 hoses, it will take 1.5 hours to fill 1 foot of water.

to fill 5 feet of water, we will need 1.5 hours x 5 feet = 7.5 hours

5 0

3 years ago

Read 2 more answers

A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102

cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

<u>Given:</u>

<em>n</em> = 1000

$\hat p$ = 0.102

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58$

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)$

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

6 0

3 years ago