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Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so .
What is the probability that a line width is greater than 0.62 micrometer?
That is
So
Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
The volume of the single crayon is 89.5 cm³, then the total volume of the crayons will be 2148 cm³. Then the correct option is D.
<h3>What is Geometry?</h3>It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
A Crayon is shown here.
There are 24 crayons in a box.
The approximate total volume of the crayons will be
Total Volume of crayons = 24 × volume of the single crayon
The crayon is the combination of the cone and the cylinder
Then the volume of the single crayon (V₁) will be
Then the Total volume will be
Total volume = 24 × 89.5
Total volume = 2148 cm³
More about the geometry link is given below.
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