The ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
<h3>How to type the ordered pairs?</h3>
The equation is given as:
y = 3^x
Let x = 0, 1 and 2
y = 3^0 = 1
y = 3^1 = 3
y = 3^2 = 9
So, we have the following ordered pairs (0,1), (1,3) and (2,9)
Hence, the ordered pairs of the equation y = 3^x are (0,1), (1,3) and (2,9)
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Answer:
Step-by-step explanation:
we wana do the same thing in the last problem
we know that FBD is a straight line so its 180 degrees
and we also know that FBE and EBD make up that straight line
so subtract 180 - 47 = 133
so the answer is 133 degrees
Answer:
Center: (3,5)
Radius: 2
Step-by-step explanation:
x² + y² - 6x - 10y + 30 = 0
Put equation into center-radius form. First regroup terms:
(x²-6x) + (y²-10y) = -30
Complete the squares:
(x²-6x+3²) + (y²-10y+5²) = -30 + 3² + 5²
(x-3)² + (y-5)² = 4 = 2²
Center: (3,5)
Radius: 2
The answer would be E. because if the determining number (The number directly after the place being rounded to. The 8 in this case) is greater than five, you round up and drop the numbers after the place being rounded to (The hundredth's place), if it's less, the number in the place being rounded to stays the same, but you still drop the numbers after it.
6cubes__________3steps
xcubes__________11steps
x=6*11\3=2*11=22 cubes
Hope that helps.
Have a nice day!!! ^^