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Goshia [24]
2 years ago
10

Find the length of BC.

Mathematics
2 answers:
gavmur [86]2 years ago
8 0

Answer:

B) 8

Step-by-step explanation:

The Segment Addition Postulate basically states that the sum of the segments of a line will equal the length of the entire line.

Thus, AB+BC=AC, and we can substitute:

AB+BC=AC

(4x+8)+(3x-4)=32

4x+8+3x-4=32

7x+4=32

7x=28

x=4

Now that we have x, we can plug it in for segment BC:

BC=3x-4

3(4)-4

12-4

8

Therefore, choice B is correct

Umnica [9.8K]2 years ago
3 0

Answer:

BC = 8

Step-by-step explanation:

AB + BC = AC

4x + 8 + 3x - 4 = 32

7x + 4 = 32

7x = 32 - 4

7x = 28

x = 28/7

x = 4

BC = 3x - 4 = 3*4 - 4 = 12 - 4 = 8

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\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>a </u><u>cone </u><u>with </u><u>base </u><u>radius </u><u>9</u><u>m</u><u>m</u><u> </u><u>and </u><u>height </u><u>1</u><u>3</u><u> </u><u>mm</u>

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We know that ,

Volume \: of \: cone =  \frac{1}{3}\pi \: r {}^{2}  h \\

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Volume =  \frac{1}{3}  \times  3.14  \times 9 \times 9 \times 13 \\  \\  \implies \: 1.05 \times 81 \times 13 \\  \\ \implies \: 1105.65 \: mm {}^{3}

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What is the solution set of 4x^2-36= 0?<br><br> (-3)<br> (3)<br> (-3,3)
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Write the equation of the ellipse with foci at (-2,2) and (4,2) and major axis of length 10 *
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Answer:

The answer to your question is   \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1          

Step-by-step explanation:

Data

Foci  (-2, 2)  (4, 2)

Major axis = 10

Process

1.- Plot the foci to determine if the ellipse is vertical or horizontal. See the picture below.

From the graph we conclude that it is a horizontal ellipse.

2.- Determine the foci axis (distance between the foci)

                  2c = 6

                    c = 6/2

                    c = 3

3.- Determine a

                  2a = 10

                    a = 10/2

                    a = 5

4.- Determine b using the Pythagorean theorem

                   a² = b² + c²

-Solve for b

                   b² = a² - c²

                   b² = 5² - 3²

                   b² = 25 - 9

                   b² = 16

                   b = 4

5.- Find the center (1, 2)  From the graph, it is in the middle of the foci

6.- Find the equation of the ellipse

                      \frac{(x - 1)^{2}}{5^{2}} + \frac{(y - 2)^{2}}{4^{2}} = 1

                       \frac{(x - 1)^{2}}{25} + \frac{(y - 2)^{2}}{16} = 1                

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