All categories

3 years ago

What is the equation of a line that is perpendicular to 8x+6y=-5?

Mathematics

1 answer:

masha68 [24]3 years ago

4 0

what is the equation of a line that is perpendicular to 8x+6y=-5 the answer is b

You might be interested in

Translate the following verbal phrase into a mathematical expression.

Pie

Answer:

how about i dont

Step-by-step explanation:

translate this

fvkndfghidrhgdughdihx

4 0

2 years ago

For what value of x do the expressions 2x+3 and 3x+-6 have the same value?

Black_prince [1.1K]

The answer is 2 because it’s -6/3 =2

3 0

3 years ago

Read 2 more answers

Hi! please help i’ll give brainliest

inessss [21]

Answer:

crust folding and faulting

Step-by-step explanation:

7 0

3 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

3 years ago

PLEASE HELP ASAP! I WILL GIVE BRAINLIEST!

olga_2 [115]

In 75 minutes you travelled 30 kilometers, so the rate is 30/75=0.4km/minute

another way is to use the two points to find the slope: m=(30-0)/(75-0)=0.4

6 0

3 years ago

Read 2 more answers