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scoundrel [369]
3 years ago
11

100 Points!!!!

Physics
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer:

Newtons/Coulomb

Explanation:

Electric field exerts a force on an electric charge.  So its unit is force divided by charge; i.e. Newtons/Coulomb

Alexxx [7]3 years ago
4 0

Answer:

<u>force per unit charge</u>

hope this helps you!!

Brainliest plsss

Explanation:

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:

E = F/q

E is the electric field strength

F is the electric force experienced by the charge

q is the positive test charge.

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Please help science final test. 6 question 22 points and I will choose brainliest.
Mama L [17]

Answer:

1. Even though matter can be found all over the Universe, you will only find it in a few forms (states) on Earth. We cover five states of matter on the site. Each of those states is sometimes called a phase. There are many other states of matter that exist in extreme environments.

2. hot buttered popcorn, burns my tongue, smells buttery, looks yellowish-white, tastes like butter, and sounds like popping corn.

3. The water is a liquid so it has the same shape had the pan.

4.Paper clips are attracted to magnets because iron has a magnectic force.

5. The first (or smallest measurement) you would see is the hash marking millimeters, which is written as "mm". 1mm equals the thickness of a dime. The unit of measure that is most often displayed on a metric ruler would be centimeters written "cm". 10mm equals 1cm and 2.5cm is about equal to 1 inch. Centimeters are displayed for viewing like inches are, marked on the ruler in increments of 1, 2, 3, 4... and so on. Usually to 30cm which is slightly less than 12 inches.

6. Mass is used to measure the weight of an object. For example, you are measuring the mass of your body when you step on to a scale. In the metric system of measurement, the most common units of mass are the gram and kilogram.

Explanation:

8 0
3 years ago
Read 2 more answers
An explosion that destroys a massive star is called a
BigorU [14]

B) is the correct answer hope this helps
4 0
3 years ago
Read 2 more answers
Two factors that affect force are:
Kamila [148]

the answer is B) friction and inertia

7 0
4 years ago
Which of the following does not affect the rate of solubility
lions [1.4K]

Answer:

Weight

Explanation:

Weight does not have any effect on solutbility.

For gases their solubility relies a lot on pressure exerted. At higher presure, gases dissolves more readily than ever. The relationship between solubility and pressure is a direct one.

Higher surface area facilitates the rate of a reaction and in essence, helps to dissolve more solute. Surface area exposes a solute to the action of more solvent which would aid solutbility.

Temperature has a high effect on solubility. An increase in temperature would make more solute dissolve in it.

3 0
4 years ago
Read 2 more answers
Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
4 years ago
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