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AfilCa [17]
3 years ago
5

See the picture to solve the question 1Question=10 points

Mathematics
2 answers:
beks73 [17]3 years ago
5 0

Answer:

1.5x+2.75y+33

Step-by-step explanation:

Call x: the hour of dogs keeping

      y: the hour of wolves keeping

The total charge for dogs keeping: 19+ 1.5x

The total charge for wolves keeping: 14+2.75y

Total cost (19+ 1.5x)+(14+2.75y)= 1.5x+2.75y+33

Kitty [74]3 years ago
3 0
The answer is 1.5x+2.75y+33
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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
What is (3+21)-4 divides by 2
katen-ka-za [31]
1. -4 times 3 and 21
2.add -12 and -84
3.-96 dived by 2
4 equals -48
3 0
3 years ago
Read 2 more answers
FRUIT
laiz [17]
2p+6a=$14
3p+9a=$21

3p+9a=21
Subtract 9a
3p=21-9a
divide all by 3
p=7-3a
plug it into start equations

2p+6a=14
2(7-3a)+6a=14
14-6a....+6a=14

this zeroes out...
5 0
3 years ago
simplify the following polynomial expression. <img src="https://tex.z-dn.net/?f=%285x%5E%7B3%7D%20%2B4x%5E%7B2%7D%20%2B6x-3%29%2
FrozenT [24]
Here is the answer hope it helps

7 0
4 years ago
Can someone help me with this problem plz
BabaBlast [244]

Answer:

4

Step-by-step explanation:

4 goes perfectly into 8 twice and 12 three times

6 0
3 years ago
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