Answer:
<em>9</em><em>0</em><em> </em><em>degree</em><em> </em><em>EFC</em><em>. </em><em>and</em><em>. </em><em>BMC</em>
<em>across</em><em> </em><em>fc</em><em>/</em><em>ma</em><em> </em>
<em>across</em><em> </em><em>ec</em><em>/</em><em>ab</em>
Answer:
h = -9
Step-by-step explanation:
Simplifying
5h + 22 + -2h = -5
Reorder the terms:
22 + 5h + -2h = -5
Combine like terms: 5h + -2h = 3h
22 + 3h = -5
Solving
22 + 3h = -5
Solving for variable 'h'.
Move all terms containing h to the left, all other terms to the right.
Add '-22' to each side of the equation.
22 + -22 + 3h = -5 + -22
Combine like terms: 22 + -22 = 0
0 + 3h = -5 + -22
3h = -5 + -22
Combine like terms: -5 + -22 = -27
3h = -27
Divide each side by '3'.
h = -9
Simplifying
h = -9
Answer:
3
Step-by-step explanation:
the initial statement is
y
∝
1
/x
to convert to an equation multiply by k the constant
of variation
y
=
k
×
1
/x
=
k
/x
to find k use the given condition
y
=
5 when x
=
6
y
=
k/
x
⇒
k
=
y
x
=
5
×
6
=
30
y
=
30
/x
when
x
=
10
then
y
=
30
/10
=
3
X= 50
Replace the x with the given number.
Y= 50-20
Y= 30
