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2 years ago

Solve these inequalities

Mathematics

1 answer:

Setler [38]2 years ago

3 0

Answer:

x>±4

x<±1

Step-by-step explanation:

Given the inequalities

x² > 16

Square root both sides

√x² > ±√16

x > ±4

The solution is x>±4

2) x² < 1

Square root both sides

√x² <±√1

x < ±1

Hence the solution is x<±1

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I need it within tomorrow please

Alenkinab [10]

Any even number raised to any power will remain even. (e.g. 2² = 4, 2³ = 8, etc)

Any odd number raised to any power will remain odd. (e.g. 1² = 1³ = ... = 1, 3⁴ = 81, etc)

So $(n+1)^{2^k}-n^{2^k}$ will always be even, since both

[even] - [odd] = [odd]

and

[odd] - [even] = [odd]

6 0

2 years ago

In a certain chemical, the ratio of zinc to copper is 4 to 19. A jar of the chemical contains 760 grams of copper. How many gram

Law Incorporation [45]

160 grams of zinc. 760/ 19 is equal to 40 so then we’d want to multiple 4 x 40 because that’s how much were growing by so then zinc is 160 grams

6 0

2 years ago

I’m pretty sure I’m wrong PLSSSS HELP

koban [17]

Your answer is definitely right good job

3 0

2 years ago

Solve for x. Round to the nearest tenth.

kondor19780726 [428]

Answer:

22.8

Step-by-step explanation:

$a^{2} +b^{2} =c^{2} \\20^{2} +11^{2} =x^{2} \\400+121=x^{2}\\\sqrt{521} =x\\\\or\\\\22.8 = x$

5 0

2 years ago

Help,anyone can help me do quetion.

3241004551 [841]

Answer:

(a) x = $128^{o}$

(b) x = $74^{o}$

Step-by-step explanation:

A. sum of angles in a polygon = (n - 2) 180

The polygon given is an irregular pentagon, where n = 5

So that;

sum of angles in a pentagon = (5 - 2) 180

= 3 x 180

= $540^{o}$

Thus,

x + 90 + 76 + 110 + 136 = $540^{o}$

x + 412 = $540^{o}$

x = $540^{o}$ - 412

x = $128^{o}$

B. The polygon given is an irregular pentagon, where n = 5.

Let the supplementary angle with angle 38 be represented by y,

y + 38 = 180

y = 180 - 38

= $142^{o}$

y = $142^{o}$

Let the supplementary angle with x be represented by z, so that;

z + 72 + 120 + 100 + 142 = $540^{o}$

z + 434 = $540^{o}$

z = $540^{o}$ - 434

= $106^{o}$

z = $106^{o}$

But, x + z = $180^{o}$

Then;

x + $106^{o}$ = $180^{o}$

x = $180^{o}$ - $106^{o}$

= $74^{o}$

x = $74^{o}$

7 0

2 years ago