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aleksandr82 [10.1K]
3 years ago
15

You roll a six-sided number cube and flip a coin. What is the probability of rolling a number less than 2 and flipping heads? Wr

ite your answer as a fraction in simplest form. The probability is .
Mathematics
2 answers:
german3 years ago
7 0

Answer:

1/12

Step-by-step explanation:

There is only one number less than two, which is 1, so you have 1/6 chance of getting a number less than two

Since a coin has two sides, you have 1/2, or 50% chance of landing on heads

If you multiply both of them, which is 1/6 times 1/2, you will get 1/12, since 1 times 1 is still 1, and 6 times 2 is 12.

Pie3 years ago
6 0

Answer:

\frac{1}{18}

Step-by-step explanation:

As the six-sided number cube had six sides, there are six events which could occur. There is only one interger less than 2 (1), therefore the probability of rolling a number less than 2 is \frac{1}{6}.

There are two events which could occur when flipping a coin. This means the probability of flipping heads is \frac{1}{2}.

To find the probability of both of these happening, you must multiply the fractions together by multiplying together both the denominators and numerators, therefore:

\frac{1}{6} ×  \frac{1}{2} = \frac{1}{18}

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If 2^(x+3) - 2x = k(2^x) what is the value of k
svlad2 [7]

Answer:

\large\boxed{C)\ 7}

Step-by-step explanation:

Use:

a^n\cdot a^m=a^{n+m}

2^{x+3}-2^x=2^x\cdot2^3-2^x=8\cdot2^x-2^x=(8-1)\cdot2^x=7\cdot2^x\\\\2^{x+3}-2^x=k(2^x)\\\\7\cdot2^x=k(2^x)\Rightarrow k=7

8\cdot2^x-2^x=8\cdot2^x-1\cdot2^x=(8-1)(2^x)=7\cdot2^x\\\\\text{distributive property:}\ a(b-c)=ab-ac

8 0
4 years ago
2x - 4y + 7x - 87<br> Helppp
xxTIMURxx [149]

Answer:

9x-4y-87

Step-by-step explanation:

2x-4y+7x-87

9x-4y-87

8 0
3 years ago
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Helen had Php7500 for shopping money. When she got home, she had Php132.75 in her pocket. How much did she spend for shopping?
Nataly_w [17]

Answer:

Step-by-step explanation:

Helen had Php7500 for shopping money

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4 0
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determinati cel mai mic multiplu comun al urmatoarelor numere naturale a-36,48,54;b-30,45,75;c-48,60,72;d-90,24,72;e-75,100,150;
fenix001 [56]
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What is the nth term of the sequence -2 -8 -18 -32 -50
andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
T_{n} = an^{2}  +bn +c

To find the value of a we just divide second difference ( -4 ) by 2:

  • a = \frac{-4}{2}= -2

Now we have:

  • T_{n}= -2n^{2}  +bn+c

Substitute n_{1} and n_{2} into the equation above:

  • T_{1} = -2(1)^{2}  +b(1) +c
  • T_{2} = -2(2)^{2}  +b(2)+c

Since T_{1} = -2 and T_{2} = -8 , after simplification we have:

  • b +c =0
  • 2b+c=0

The solution of this system is:

  • b=0, c =0

The general term is :

T_{n} = -2n^{2}

6 0
2 years ago
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