<u>Given</u>:
Given that the isosceles trapezoid JKLM.
The measure of ∠K is 118°
We need to determine the measure of each angle.
<u>Measure of ∠L:</u>
By the property of isosceles trapezoid, we have;
![\angle K+\angle L=180^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20K%2B%5Cangle%20L%3D180%5E%7B%5Ccirc%7D)
![118^{\circ}+\angle L=180^{\circ}](https://tex.z-dn.net/?f=118%5E%7B%5Ccirc%7D%2B%5Cangle%20L%3D180%5E%7B%5Ccirc%7D)
![\angle L=62^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20L%3D62%5E%7B%5Ccirc%7D)
Thus, the measure of ∠L is 62°
<u>Measure of ∠M:</u>
By the property of isosceles trapezoid, we have;
![\angle L \cong \angle M](https://tex.z-dn.net/?f=%5Cangle%20L%20%5Ccong%20%5Cangle%20M)
Substituting the value, we get;
![62^{\circ}=\angle M](https://tex.z-dn.net/?f=62%5E%7B%5Ccirc%7D%3D%5Cangle%20M)
Thus, the measure of ∠M is 62°
<u>Measure of ∠J:</u>
By the property of isosceles trapezoid, we have;
![\angle J \cong \angle K](https://tex.z-dn.net/?f=%5Cangle%20J%20%5Ccong%20%5Cangle%20K)
Substituting the value, we get;
![\angle J =118^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20J%20%3D118%5E%7B%5Ccirc%7D)
Thus, the measure of ∠J is 118°
Hence, the measures of each angles of the isosceles trapezoid are ∠K = 118°, ∠L = 62°, ∠M = 62° and ∠J = 118°
28 in^2
Divide shape into one rectangle and two squares:
Area of rectangle:
10 x 2 = 20 in^2
Area of one square:
2 x 2 = 4 in^2
Multiply that by 2 because we have 2 squares similar in size:
4 in^2 x 2 = 8 in^2
Add the area of the rectangle and two squares:
20 in^2 + 8 in^2 = 28 in^2
Have a nice day
Hope this helps!
Answer:
The answer is B. n+3=7
Step-by-step explanation:
^^^^^^^
Answer:10
Step-by-step explanation:
its the first 1. b.
Step-by-step explanation:
nb. b. b b b bcbcbc