There are two consecutive positive even integers such that the square of the first is 364 more than five times the second. What
are the two numbers?
1 answer:
Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
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That is equivalent to 8√10
4 x 3 = 12
1 x 3 = 3
12 + 3 = 15
answer
15 square units
5(15)+(15)(15)=75+225
=300
Answer:
Your answer should be B. x + -1 +- √17
Step-by-step explanation:
A=πr2=π·92≈254.469
your answer is 254.469