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erastova [34]
3 years ago
12

3x+-6+2 > = 5x -8......can someone please solve this

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

x ≤ 2

Step-by-step explanation:

If you referencing ">=" as greater than or equal to, follow the solution below:

Solve:

3x - 6 + 2 ≥ 5x - 8

Combine like terms.

3x - 4 ≥ 5x - 8

Subtract 5x from both sides.

-2x - 4 ≥ -8

Add 4 to both sides.

-2x ≥ -4

Divide both sides by -2, while flipping the inequality as well since you're dividing by a negative number.

x ≤ 2

Your answer would be x ≤ 2

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If EF = 5w + 20, FG = 7w + 28, and EG = 72, find the value of w. Find EF and FG
IrinaK [193]

Answer:

 w = 2, EF = 30 , FG = 42

Explanation:

We have EF = 5w + 20  and FG = 7w + 28

 Since these points E, F and G are col-linear points we have.

    EG = EF + FG

  And given that EG = 72

So, EF+EG = 72

     5w + 20 + 7w + 28 = 72

     12w + 48 = 72

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       w = 2

So EF = 5w + 20 = 5x2 + 20 = 30

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3 years ago
The slope intercept form of (-4, 8) and (9, 8)
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Step 2: Substitute into the slope intercept equation

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4 years ago
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
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