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LekaFEV [45]
3 years ago
12

Help Would Be Greatly Appreciated :)

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

n is y=\frac{1}{2}x+b, p is y=\frac{1}{2}x-5, and r has infinitely many different lines that have this property.

Step-by-step explanation:

If two lines have no solutions, that means that they are parallel. The slopes of two lines are the same if they are parallel. So n's slope is \frac{1}{2}. The y-intercept can be anything except -5, or +b. If two lines have infinitely many solutions, those two lines are exactly the same. So p is just m. If two lines have one and only one solution, that just means the slopes and y-intercepts are different. Since we don't know anything else about line r, we an't model an equation for it.

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g Farmer Violet wants to enclose one 990 square foot rectangular area of land using fencing. One side will use special fencing c
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Answer:

Sides of the rectangular area:

x =  30  f

y =  33  f

Step-by-step explanation:

Let´s call   x  and y the sides of the rectangular area

A = x*y  = 990          y  = 990/x

The function cost is:

C = Costs ( sides x)  + costs ( sides y )

Cost of sides x    =  12*x +  10x

Cost of sides y    =  10*y  +  10 *y   =  2*10*y  = 20*y

C = 12*x + 10*x + 20*y =  22*x  + 20*y

The function cost as function of x is:

C(x)  = 22*x + 20*(990/y)  =  22*x  +  19800/x

Tacking derivative on both sides of the equation:

C´(x)  = 22  + [ - 19800/x²]

C´(x) = 0       22  - 19800/x²  =  0

Solving for x

22*x²  - 19800  =  0

22x²  =  19800

x² =  19800/22 =  900

x₁,₂ = ± 30        We dismiss negative root ( we never have negative lenghts)

Then     x =  30 f

And  y  =  990 / 30      y  = 33  

To see if x = 30 is a minimum for function C(x) we evaluate the second derivative.

C´´(x) = 2*x* 19800/x⁴      

C´´ (x) = 39600/x³    so C´´ is always greater than 0 then C (x) has a minimum at x = 30

Sides of the rectangular area are:

x  =  30

y  =  33

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