You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.
C - A = AC
0 - (-6) = AC Cancel out the double negative
0 + 6 = AC
6 = AC
Now, find another segment that also has a length of 6.
D - B = BD
2 - (-2) = BD Cancel out the double negative
2 + 2 = BD
4 = BD
4 ≠ 6
E - B = BE
4 - (-2) = BE Cancel out the double negative
4 + 2 = BE
6 = BE
6 = 6
So, the segment congruent to AC is B. BE .
Think of the entire population of 6th graders here. 3/7 are boys and 4/7 are girls. 5/8 of these boys are in Ms. Jones' class; that fraction would be (5/8)(3/7), or 15/56. This 15/56 represents the fraction of the entire sixth grade class who are in Ms. Jones' class.
The equation of a line can be expressed in slope intercept form as y = mx + b where m is the slope and b is the y-intercept. Horizontal lines have a slope of 0, so the equation is simply y=b.
The y value of the point given is -5, so the answer is y = -5.
The answer to the question
Answer:
[-6 ± √26]\2
Step-by-step explanation:
y(x) is no such thing.
Now, since this is unfactorable, apply the Quadratic Formula, x = [-b ± √(b² - 4ac)]\2a:
[-12 ± √104]\4
Divide everything by 2 to get the above answer.
I am joyous to assist you anytime.
