This table shows values that represent an exponential function.

What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?

Fantom [35]

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is $M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

Let ( $x_1,y_1$ ) be the point (3.5, 2.2) and ( $x_2, y_2$ ) be the point (1.5, -4.8)

substituting the points in the formula

$M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)$

$=\left(\frac{5}{2}, \frac{-2.6}{2}\right)$

$=\left(2.5,-1.3\right)$

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

8 0

2 years ago

Solve the proportion x/12.6=45/63

NNADVOKAT [17]

Answer:

x = 9

Step-by-step explanation:

solve using cross multiplication

63(x) = 45(12.6)

63x = 567

x = 9

5 0

3 years ago

Read 2 more answers

NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)

olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level PA (men) PA (Women)

Sedentary 1.00 1.00

Low 1.11 1.12

Active 1.25 1.27

Very Active 1.48 1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

$EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)$

$= 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962$

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0

2 years ago

Find the missing angles in the parallelogram

Setler [38]

You know that D is 35° cause of the angle next to F. and <E=180-(120+35) so E is 25°

6 0

3 years ago

The height of a punted football can be modeled by the function: f(x) = -.0079 x2 + 1.8x + 1.5. In this equation, f(x) is the hei

mars1129 [50]

Answer:

Step-by-step explanation:

The function used to represent the height of a punted football can be modeled as

f(x) = -.0079x² + 1.8x + 1.5

Where f(x) is the height in feet, and x is the horizontal distance, also in feet.

a) when the ball was punted, x = 0, therefore, the height of the punted ball would be

f(x) = -.0079(0)² + 1.8(0) + 1.5

f(x) = 1.5 feet

The height is 1.5 feet

b) The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height reached by the punted ball.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = - 0.0079

b = 1.8

Vertex = - - 1.8/0.0079 = 227.84 feet

So the maximum height of the punt is 227.84 feet

3 0

2 years ago