Question

Can u guys help me with these two problems?? for the first one I got 76 ,but I don't think is right.

Answer 1

Answer:

See below

Step-by-step explanation:

15)

In the right-angle triangle, once one of the angles is 44º, then, the unknown angle is $x$.

$180 = 44 + 90 + x$

$180 = 134 + x$

$x= 46$

The angle $y$ of the other triangle plus the angle $x$ of the right-angle triangle is equal to 90º, therefore they are complementary angles.

So,

$90 = x + y$

$90 = 46 + y$

$y=44$

To find ?, we have

$180 = 58 + 44 +?$

$180 = 58 + 44 +?$

$? =78$

16)

The sum of the internal angles of the triangle with angles 50º and 25º is equal to 180º, therefore, the other angle is

$180 = x + 50 + 25\\180 = x+ 75\\x=105$

Once the angles are opposite, they are the same. For the triangle with the 36º angle, we have

$180 = 36 + 105 + y$

$180 = 141+ y$

$y=39$

$?=39$