Answer:
19
Step-by-step explanation:
ez pz lemon squeezie
Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
The correct answer is C
Sigma Notation is when we take all of the whole numbers between the starting point (which can be found as the number under the sigma sign) and the end number (which can be found above the sigma sign). Therefore, we will add together all of the values of 3k + 2 for when k is equal to all of the numbers between 2 and 7. So, let's evaluate each one first.
When k = 2
3(2) + 2 = 8
When k = 3
3(3) + 2 = 11
When k = 4
3(4) + 2 = 14
When k = 5
3(5) + 2 = 17
When k = 6
3(6) + 2 = 20
When k = 7
3(7) + 2 = 23
So we know we have the following.
8 + 11 + 14 + 17 + 20 + 23
Now for the number after the comma, we are just looking for the answer of them all added together. So the final answer should be
8 + 11 + 14 + 17 + 20 + 23, 93
Answer:
5
Step-by-step explanation:
(4+11)/3 = 15/3 = 5
Answer:
8+12f
hope this helps
have a good day :)
Step-by-step explanation:
