The answer is A they both get payed 6 dollars per hour
Answer:
The maximum volume of the open box is 24.26 cm³
Step-by-step explanation:
The volume of the box is given as
, where
and
.
Expand the function to obtain:

Differentiate wrt x to obtain:

To find the point where the maximum value occurs, we solve



Discard x=3.54 because it is not within the given domain.
Apply the second derivative test to confirm the maximum critical point.
, 
This means the maximum volume occurs at
.
Substitute
into
to get the maximum volume.

The maximum volume of the open box is 24.26 cm³
See attachment for graph.
thats the graph for the equation.
hope it helps
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.