52-y+4
(2/3) (52-y+4)+3=25 ;; (1/3) get off, so (2/3) left
(2/3)(52-y+4) =22
52-y+4=33
-y=-23
y=23
Answer:
I think it is J if not it may be H if they are both wrong i am so so sorry
Step-by-step explanation:
Answer:
22x + 100 = 25x + 70, 10 yards
Step-by-step explanation:
Set the number of square yards of carpeting as x.
So, the cost of Country Carpets is: 22 * x + 100
And the cost of City Carpets is: 25 * x + 70.
In order for the costs to be the , the equations need to be equal.
22x + 100 = 25x + 70
Subtract 22x from both sides.
100 = 3x + 70
Subtract 70 from both sides.
3x = 30
x = 10
10 square yards
Let U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}, A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, and C = {1, 2, 4, 5, 8, 9}. List the element
Leto [7]
Answer:



Step-by-step explanation:
Required
Determine



Solving 
implies that elements in U but not in C
Since




<em>Because there's no intersection between both</em>
Solving 
First, we need to determine A n C




Solving 
First, we need to determine B n C


So:


C & A I believe because 2+3 is 5 so that’s 5x