Answer:
2/3
Step-by-step explanation:
-7 - -1 = -6
-5 - 4 = -9
-6/-9= 2/3
Answer:
Equation of the circle (x-3)²+(y-5)²=(6.4)²
x² -6x +9 +y² -10y +25 = 40.96
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given endpoints of diameter P(−2, 1) and Q(8, 9)
Centre of circle = midpoint of diameter
Centre = 
Centre (h, k) = (3 , 5)
<u><em>Step(ii):-</em></u>
The distance of two end points
PQ = 
PQ = √164 = 12.8
Diameter d = 2r
radius r = d/2
Radius r = 6.4
<u><em>Final answer:-</em></u>
Equation of the circle
(x-h)²+(y-k)² = r²
(x-3)²+(y-5)²=(6.4)²
x² -6x +9 +y² -10y +25 = 40.96
x² -6x +y² -10y = 40.96-34
x² -6x +y² -10y -7= 0
Answer:
<h2>C) (negative 1, one-half), (0, 1), (1, 2), (2, 4)</h2>
Step-by-step explanation:
The set C could be generated by an exponential function. The main reason is that exponential functions hava a restricted range, it can't have negative numbers or the number zero, because power can only be equal or greater than 1.
Additionally, for all exponentials, a null exponent gives 1 as an answer, so point (0, 1) is always present in an exponential function.
Therefore, the right answer is C.
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
