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slavikrds [6]
3 years ago
9

Don’t know the answer to this?

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

Step-by-step explanation:

The first one.

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Given the rule: an=7(1/2)n-1 identify the first term
Shkiper50 [21]

Answer:

  • using the rule given: 2.5
  • using an exponential rule: 7

Step-by-step explanation:

Evaluating the linear rule given, for n = 1, we have ...

  a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5

_____

We suspect you may intend the exponential function ...

  an = 7(1/2)^(n-1)

Then, for n = 1, we have ...

  a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7

_____

When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.

3 0
3 years ago
I need help on this question
deff fn [24]

Answer:

C

Step-by-step explanation:

ITS ALWAYS C UWU

6 0
3 years ago
What is the greatest common factor of 16 and 48?​
Anna11 [10]

Answer:

16

Step-by-step explanation:

We can list out each of the numbers' prime factors first before deciding their greatest common factor.

16: 2 × 2 × 2 × 2

48: 2 × 2 × 2 × 2 × 3

As you can see the bolded parts, these are the common factors of the two numbers. To find the greatest common factors, we just have to multiply all their common factors together.  

Greatest common factor of 16 & 48: 2 × 2 × 2 × 2 = 16

7 0
3 years ago
Read 2 more answers
But how is is it 1 hour and 45 minutes(someone please respond this is due tomorrow)I need work
astraxan [27]
Because it is every hour there's 60min so that's and hour the the next 45 min are different
4 0
3 years ago
In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?
vichka [17]

Answer:

x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-10 and c=6

Putting values in the quadratic formula

x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}

So, x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}

3 0
3 years ago
Read 2 more answers
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