To determine the 'intervals of increase' and 'intervals of decrease' we can refer to the graph with respect to the x - axis.
• Knowing that t = x - axis, the 'intervals of increase' as an inequality would be 1 < x < 3, and 4 < x < ∞. Therefore we have our intervals of increase as (1,3) and (4, ∞).
• Respectively our 'intervals of decrease' as inequalities would be - ∞ < x < 1, and 3 < x < 4. Our intervals of decrease would then be (- ∞, 1) and (3,4).
• We are left with our local extrema and absolute extrema. Now remember the absolute extrema is the absolute lowest point in the whole graph, while the local extrema is the lowest point in a restricted interval. In this case our local extrema is our maximum, (3,1). But this maximum is not greater than the starting point (0, 4) so it appears, and hence their is no absolute extrema.
Use midpoint formula:
8+2/2 ,-3+9/2
= 5,3.
The second option
Answer: 15 ounces of wine
Step-by-step explanation:
A five-ounce glass of wine which is 12 percent alcohol), a 12-ounce of beer, and a 1.5 ounces of 86-proof liquor all have approximately thesame amount of alcohol.
Therefore, 36 ounces of beer will be:
= 36 × 5/12 ounces of wine
= 15 ounces of wine
We know that
[surface area of sphere]=4πr²
[surface area of hemisphere]=2πr²
(sphere)
r=12 in
[surface area of sphere ]=4π12²--------> 576π in²
(hemisphere)
r=12 in[surface area of hemisphere ]=2π12²--------> 288π in²
[the ratio of the surface area of sphere to the surface area of hemisphere]
=576π/288π-------> 2
the answer is
the ratio is 2