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Maurinko [17]
3 years ago
13

Find the value of the lesser root of x 2-8x+7=0

Mathematics
1 answer:
mariarad [96]3 years ago
7 0
Hi there! The answer is x = 1

{x}^{2}  - 8x + 7 = 0

(x - 7)(x - 1)
Rule AB = 0, gives A = 0 or B = 0

x - 7 = 0 \:  \: or \:  \: x - 1 = 0 \\ x = 7 \:  \:  \:  \:   \:  \:  \:  \:  \: or \:  \: x   = 1
Therefore, the smallest of both roots is x = 1.
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