Question

Find the value of the lesser root of x 2-8x+7=0

Answer 1

Hi there! The answer is x = 1

${x}^{2} - 8x + 7 = 0$

$(x - 7)(x - 1)$
Rule AB = 0, gives A = 0 or B = 0

$x - 7 = 0 \: \: or \: \: x - 1 = 0 \\ x = 7 \: \: \: \: \: \: \: \: \: or \: \: x = 1$
Therefore, the smallest of both roots is x = 1.