Which factor will most likely reduce the carrying capacity of a squirrel population in a forest?

What is the difference between totipotent, pluripotent, and multipotent stem cells? Discuss the three main types of stem cells a

Brums [2.3K]

Answer:

Totipotent (omnipotent) stem cells can give rise to any of the 220 cell types found in an embryo as well as extra-embryonic cells (placenta). Pluripotent Stem Cells Pluripotent stem cells can give rise to all cell types of the body (but not the placenta). Multipotent Stem Cells Multipotent stem cells can develop into a limited number of cell types in a particular lineage.

Explanation:

6 0

4 years ago

If a dominant allele of one gene, a, is necessary for hearing in humans, and the dominant allele of another gene, b, results in

yKpoI14uk [10]

The correct genotypes of the parents are AaBb and Aabb

In a cross of these two genotypes presented in the image below, 5/8 of the offspring would be deaf.
The individuals marked with a red square would be deaf because of the recessive aa alleles and the rest of the progeny that is marked with green would be deaf because of the presence of the B dominant allele.

6 0

3 years ago

If a rabbit receives 150 calories of energy from eating carrots, how much of

joja [24]

Carrot- 1500
rabbit- 150
snake- 15
hawk- 1.5

4 0

3 years ago

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How will the filtration rate in the renal corpuscles be affected if a kidney stone creates a blockage of the urinary tract?

Leviafan [203]

Answer:

There will be a progressive fall in glomerular filtration rate.

Explanation:

The glomerular filtration rate,GFR, shows how well the Kidney is functioning or working. When the Kidney is not working well, it doesn't filter the way it should.

Note that, Glomerular filtration is the process of removing wastes and excess fluid to become part of the urine, by the kidney.

7 0

3 years ago

1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently

maria [59]

Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

Available data:

Flower position: Axial (A) is dominant to Terminal (a)

Stem length: Tall (T) is dominant to dwarf (t)

Seed shape: Round (R) is dominant to wrinkled (r)

Cross:

Parental) AaTtDd x AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

AA= 1/4

Aa =2/4

aa = 1/4

TT = 1/4

Tt = 2/4

tt = 1/4

DD = 1/4

Dd = 2/4

dd = 1/4

This is the same as developing a Punnett square for each gene separately.

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4 x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

4 0

3 years ago

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