<span>The answer is B. 72.25 percent.
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1 </em>and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq</em> are the frequencies of the genotypes.
<span>The <em>p</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>P</em> allele frequency (<em>p</em>), the formula <em>p + q = 1</em> can be used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>P</em> allele (<em>p</em>), it is easy to determine the frequency of the <em>PP </em>genotype (<em>p²</em>):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
Protein, the building blocks of proteins are amino acids, different sequences and combinations of these amino acids result in huge numbers of proteins which have a variety of functions.
Answer:
cysteine
Explanation:
The anticodon for ACA is UGU
in the left column find the U. From the top column find the G. From the right column find the last U. The amino acid at that location is cysteine
Answer:
Question is not presented
Explanation:
