All categories

2 years ago

-2/3x+7(3/7-3/7x) -12 divided by 6*3

Mathematics

1 answer:

Anna71 [15]2 years ago

5 0

Answer:

x = (-27)/11

Step-by-step explanation:

Solve for x:

(-11 x)/54 - 1/2 = 0

Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:

(-27)/54 - (11 x)/54 = 0

(-27)/54 - (11 x)/54 = (-11 x - 27)/54:

(-11 x - 27)/54 = 0

Multiply both sides of (-11 x - 27)/54 = 0 by 54:

(54 (-11 x - 27))/54 = 54×0

(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:

-11 x - 27 = 54×0

0×54 = 0:

-11 x - 27 = 0

Add 27 to both sides:

(27 - 27) - 11 x = 27

27 - 27 = 0:

-11 x = 27

Divide both sides of -11 x = 27 by -11:

(-11 x)/(-11) = 27/(-11)

(-11)/(-11) = 1:

x = 27/(-11)

Multiply numerator and denominator of 27/(-11) by -1:

Answer:x = (-27)/11

You might be interested in

83/6 as a mixed number

jonny [76]

$\frac{83}{6}=13\frac{5}{6}$

8 0

2 years ago

The skating rink rented 218 pairs of skates during the month of April and 3 times that many in May. How many pairs of skates did

Marrrta [24]

Answer: Total number of pairs =872

Step-by-step explanation:

Since we have given that

Number of pairs of skates during the month of April =218

Number of pairs of skates during the month of May =3 × 218=654

As we know that total means altogether in which we perform the additive operation.

Total pairs of skates the skating rent during April and May = 218+654=872

∴ Total number of pairs =872

7 0

2 years ago

Read 2 more answers

A manufacturing plant earned $80 per man-hour of labor when it opened. Each year, the plant earns an additional 5% per man-hour.

baherus [9]

A function that gives the amount that the plant earns per man-hour t years after it opens is $\mathrm{A}(\mathrm{t})=80 \times 1.05^{\mathrm{t}}$

<h3><u>Solution:</u></h3>

Given that

A manufacturing plant earned $80 per man-hour of labor when it opened.

Each year, the plant earns an additional 5% per man-hour.

Need to write a function that gives the amount A(t) that the plant earns per man-hour t years after it opens.

Amount earned by plant when it is opened = $80 per man-hour

As it is given that each year, the plants earns an additional of 5% per man hour

So Amount earned by plant after one year = $80 + 5% of $80 = 80 ( 1 + 0.05) = (80 x 1.05)

Amount earned by plant after two years is given as:

$=(80 \times 1.05)+5 \% \text { of }(80 \times 1.05)=(80 \times 1.05)(1.05)=80 \times 1.052$

Similarly Amount earned by plant after three years $=80 \times 1.05^{t}$

$\begin{array}{l}{\Rightarrow \text { Amount earned by plant after } t \text { years }=80 \times 1.05^{t}} \\\\ {\Rightarrow \text { Required function } \mathrm{A}(t)=80 \times 1.05^{t}}\end{array}$

Hence a function that gives the amount that the plant earns per man-hour t years after it opens is $\mathrm{A}(t)=80 \times 1.05^{t}$

5 0

3 years ago

5x+14=k for x <br> Solve this problem

Nimfa-mama [501]

I think it's ×=2.5 or it's x=1 or it's x= 19

5 0

2 years ago

0.5s +1=7 + 4.5s<br> S =

kvv77 [185]

Answer:

$s = -\frac{3}{2}$

Step-by-step explanation:

Solve for the value of $s$ :

$0.5s + 1 = 7 + 4.5s$

-Combine both $0.5s$ and $4.5s$ by subtracting $0.5s$ by $4.5s$ :

$0.5s + 1 - 4.5s = 7 + 4.5s - 4.5s$

$-4s + 1 = 7$

-Subtract $1$ to both sides:

$-4s + 1 - 1 = 7 - 1$

$-4s = 6$

-Divide both sides by $-4$ :

$\frac{-4s}{-4} = \frac{6}{-4}$

$s = -\frac{3}{2}$

So, the value of $s$ is $-\frac{3}{2}$ .

3 0

2 years ago