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3 years ago

Graph the equation. Y=2x+3

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

Is this what you looking for??

Alisiya [41]3 years ago

3 0

Answer:

bro go to (0,3) and go up 2 and right 1 and place a dot and keep doing that till you cant anymore then go back to point (0,3) and go down 2 left 1 and place a dot and keep doing that till you cant any more then draw a line through the dots simple

Step-by-step explanation:

because 2x is the slope or 2/1x is the slope witch means you go to y intercept 3 or (0,3) and you do rise over run the slope 2/1 rise being 2 run being 1 see simple

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List three tools and equipment needed for baking

vivado [14]

Answer:

oven, whisk, pan

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the reciprocal of 17 1/2

Aneli [31]

Answer:

2/35

Step-by-step explanation:

If you convert 17 1/2 to a improper fraction, it becomes 35/2. Then to find the reciprocal, flip the numerator and denominator. So, 2/35

Hope this helps!

4 0

2 years ago

NEED HELP DUE TODAYY!!!

svetoff [14.1K]

Answer:

144

Step-by-step explanation:

5x + 4x = 7x + 32

9x = 7x + 32

2x = 32

x = 16

7(16) + 32 = 144

I think this is correct

pls mark brainliest if good

7 0

3 years ago

Jackie cut a 2 yard spool into 5 equal lengths of ribbon?

lidiya [134]

5 units = 2 yd.
1 unit = 2/5
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6 0

3 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago