2 years ago

Pls help A bag contains 40 colored tiles. There are 12 red, 17 blue, 8 yellow and 3 green. One tile is drawn at

1 answer:

4 0

D blue I think, it has the most tiles in the bag 17/40 while all the other fractions are smaller decreasing their chances

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2x – 5 > 3 and -4x + 7 < -25

KATRIN_1 [288]

Answer:

Step-by-step explanation:

5 0

2 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago

"Find x" I managed to get -6/2c, I just want to double check if that is correct

Soloha48 [4]

- 6/2c is the correct solution

collect like terms : 3cx - cx = 2cx

hence 2cx = - 6

dividing both sides by 2c gives x = - 6/2c

7 0

3 years ago

3x≤−5/4 please help me so i can pass this assignment

RSB [31]

Hope this helps !!!!!

6 0

2 years ago

What is the answer to this?<br> Thank you

Andre45 [30]

7y+11+7y+11+7y+11=180(A.S.P)
21y+33=180
21y=180-33
21y=147
y=147/21
y=7

y=7

6 0

3 years ago

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