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Minchanka [31]
3 years ago
8

A. 2x = 5 What would be the answer I don’t know anyone help me before the 28th

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

2.5

Step-by-step explanation:

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Answer the question provided in the picture below.
FromTheMoon [43]

Answer:

Finding area: multiply length by width (multiply the top length by the side length)

Finding perimeter: Add the lengths of all of the sides together

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If r=10 and s=31 find R. Round to the nearest tenth
Vsevolod [243]

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "R":

 \alpha =arctan(\frac{opposite}{adjacent})

You know that you need to find the measure of "R" and r=10 (which is the opposite side) and s=31 (which is the adjacent side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get:

R=arctan(\frac{10}{31})\\\\R=17.9\°

3 0
3 years ago
Read 2 more answers
Someone help please
Alla [95]

Answer:  Choice A

\tan(\alpha)*\cot^2(\alpha)\\\\

============================================================

Explanation:

Recall that \tan(x) = \frac{\sin(x)}{\cos(x)} and \cot(x) = \frac{\cos(x)}{\sin(x)}. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \tan(\alpha)*\cot^2(\alpha)\\\\ is identical to \frac{\cos(\alpha)}{\sin(\alpha)}\\\\

Therefore, \tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \tan(\alpha)*\cot^2(\alpha)\\\\ is the same as \frac{\cos(\alpha)}{\sin(\alpha)}\\\\ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0
3 years ago
How many 100 make 3200?
Gelneren [198K]
32!

32 100s can go into the number 3200! Hope this helped!
4 0
3 years ago
-11 , -15, -19 is an arithmetic sequence <br> Find the nth term of the sequence
pochemuha

Answer:-47


Step-by-step explanation:

1# 11+4=15

2# 15+4=19

3# 19+4=23

4# 23+4=27

5# 27+4=31

6# 31+4=35

7# 35+4=39

8# 39+4=43

9# 43+4=47

REMEBER its negative not positive.



6 0
3 years ago
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