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navik [9.2K]
2 years ago
15

What is 3r³/2rhow do I go about solving it thanks​

Mathematics
2 answers:
Mars2501 [29]2 years ago
7 0

Answer:

solving the expression \frac{3r^3}{2r} we get \mathbf{\frac{3}{2}r^2}

Step-by-step explanation:

We need to solve the expression: \frac{3r^3}{2r}

For solving exponents in the fraction we can use the exponent rule:\frac{a^m}{a^n}=a^{m-n}

Applying the above rule and solving:

\frac{3r^3}{2r}\\=\frac{3}{2}r^{3-1}\\\\=\frac{3}{2}r^2

So, solving the expression \frac{3r^3}{2r} we get \mathbf{\frac{3}{2}r^2}

natulia [17]2 years ago
6 0

Answer:

3r^2 /2

Step-by-step explanation:

r^3 cancels out r in the denominator remaining with r^2 in the numerator.

so 3r^2/2

= 3r^2 /2

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Given z=4+3i evaluate z​
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Answer:

5

Step-by-step explanation:

Assuming we want to evaluate |z|, given that, z=4+3i.

Then, by definition of modulus,

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Step-by-step explanation:

8 0
3 years ago
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Use set notation to write the members of the following set, or state that the set has no members. Odd numbers between 2 and 82 t
adell [148]

Let the set of all Odd multiples of 9 between 2 and 82 be denoted by D, then, using set-builder notation,

D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}

The odd multiples of 9, m, in the range 2\le m \le 82 form the set

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Each member of the set is a term of the arithmetic progression

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Putting these facts together, we get the result

D=\{ 18n+9 \mid n \in \mathbb{N}, 0\le n\le 4 \}

Learn more about set-builder notation here: brainly.com/question/17238769

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