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navik [9.2K]
3 years ago
15

What is 3r³/2rhow do I go about solving it thanks​

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0

Answer:

solving the expression \frac{3r^3}{2r} we get \mathbf{\frac{3}{2}r^2}

Step-by-step explanation:

We need to solve the expression: \frac{3r^3}{2r}

For solving exponents in the fraction we can use the exponent rule:\frac{a^m}{a^n}=a^{m-n}

Applying the above rule and solving:

\frac{3r^3}{2r}\\=\frac{3}{2}r^{3-1}\\\\=\frac{3}{2}r^2

So, solving the expression \frac{3r^3}{2r} we get \mathbf{\frac{3}{2}r^2}

natulia [17]3 years ago
6 0

Answer:

3r^2 /2

Step-by-step explanation:

r^3 cancels out r in the denominator remaining with r^2 in the numerator.

so 3r^2/2

= 3r^2 /2

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19/24 as a decimal rounded to the nearest hundredth
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0.79

Step-by-step explanation:

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3 years ago
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Solve: 2/x+1/3=1/y for y.
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Answer:

y=3x/6+x

Step-by-step explanation:

7 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
What is the area of the rectangle<br> below?
DiKsa [7]

Answer:

Area of rectangle = l×b= 3 1/4 × 1 1/2

= 31/8 = 4 7/8

4 0
2 years ago
HELP HELP ASAP THANKS
mylen [45]

Answer:

Step-by-step explanation:

the range is written as (min y value, max y value)

the domain is written as (min x value, max x value)

question 6

the min y value on the picture is -3, while the arrows point upward, so the max is infinity, so the domain is [-3,∞), with a bracket on -3 because -3 is included

[-3,∞)

question 7

the min x value is the leftmost point, which is at x = -3, while the max is the rightmost point at x = 3, and both are included in the domain so there should be brackets on both

[-3,3]

question 8

the arrow on the left points to the left and up infinitely, so the min is -∞, the arrow on the right points to the right and up infinitely, so the max x value is ∞

(-∞,∞)

question 9

the min value is the bottommost point at y = -2, and the arrow points upward infinitely so the max y value is ∞

[-2,∞)

question 10

the arrow on the left points to the left infinitely so the min x value is -∞, the arrow on the right points to the right infinitely so the max x value is ∞

(-∞,∞)

8 0
3 years ago
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