The normal boiling point<span> of </span>ethanol<span> is 78.4 degrees C and, at thistemperature, </span>the vapor pressure<span> is 101325 Pascals (Pa) or 760manometric units
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Answer:
Energy emitted by photon = 45.06 × 10−32 J
Explanation:
Energy of photon is given by E = hf
where
h is the Planck's constant whose value is 6.626×10−34J⋅s
f is the frequency of photon
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given that
f = 6.8 x 104 Hz
1 HZ = 1 s^-1
E = 6.626×10−34J⋅s * 6.8 x 10^4 Hz
E = 45.06 × 10−32 J
Thus,
Energy emitted by photon is 45.06 × 10−32 J
Answer:
The pH of the solution is 3.0
Explanation:
Considering:
Or,
Given :
For :
Molarity = 0.0030 M
Volume = 100 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 100×10⁻³ L
Thus, moles of :
Moles of = 0.0003 moles
Volume added = 200 mL
Total volume = 200 + 100 mL = 300 mL = 0.3 L
Thus,
SInce, it is strong acid. Thus, [H⁺] = 0.001 M
pH is defined as the negative logarithm of the concentration of hydrogen ions.
Thus,
pH = - log [H⁺] = - log 0.001 = 3.0
<u>The pH of the solution is 3.0</u>