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Oksi-84 [34.3K]
3 years ago
8

What is the total number of moles of H2SO4 needed to prepare 5.0 liters of a 2.0 M solution of H2SO4

Chemistry
2 answers:
Lerok [7]3 years ago
5 0

Answer:

10

Explanation:

forsale [732]3 years ago
3 0
The molarity of H2SO4 is the number of moles in 1 L of solution.
The molarity is 2.0 mol/L
This means that there should be 2 moles in a 1 L solution to make up this molarity.
In this case we need to make up a 5 L solutions with that molarity. Then the amount of moles required are - 2 mol/L x 5 L = 10 mol
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Green light has a frequency of 6.01 x 10^14 Hz. What is the wavelength? (Round to the nearest hundredth) *​
Ivahew [28]

Answer:

4.99 x 10⁻⁷ meters or 499 nanometers

Explanation:

Use the formula:

λ = c/ν, where λ = wavelength, c = the speed of light (it's constant, 2.998 x 10⁸ m/s), and ν = frequency

λ = (2.998 x 10⁸ m/s)/(6.01 x 10¹⁴ 1/s)

λ = 4.98835 x 10⁻⁷

Round to nearest hundreth and you get 4.99 x 10⁻⁷ meters, or 499 nanometers.

7 0
3 years ago
Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:
Lubov Fominskaja [6]

Answer:

\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}

4 0
3 years ago
Read 2 more answers
According to the reaction below, what mass of oxygen gas is required to produce 22 g of carbon dioxide?
alisha [4.7K]
The answer is B)4.0g
6 0
4 years ago
(b) Suggest why passing water through the filter is an important step in the home water
Snezhnost [94]

Explanation:

Water filtration is the process of removing or reducing the concentration of particulate matter, including suspended particles, parasites, bacteria, algae, viruses, and fungi, as well as other undesirable chemical and biological contaminants from contaminated water to produce safe and clean water for a specific purpose ...

5 0
3 years ago
What is the percent composition of NaHCO3?
zhuklara [117]

Answer:

                Option-C (27.36% Na, 1.20% H, 14.30% C, and 57.14% O)

Explanation:

<em>Percent Composition</em> is defined as the <u><em>%age by mass of each element present in a compound</em></u>. Therefore, it is a relative amount of each element present in a compound.

Calculating Percent Composition of NaHCO₃:

1: Calculating Molar Masses of all elements present in NaHCO₃:

              a) Na  =  22.99 g/mol

             b) H  =  1.01 g/mol

              c) C  =  12.01 g/mol

              d) O₃  =  16.0 × 3 =  48 g/mol

2: Calculating Molecular Mass of NaHCO₃:

              Na  =  22.99 g/mol

             H    =  1.01 g/mol

              C    =  12.01 g/mol

              O₃  =  48 g/mol

                       ----------------------------------  

Total                  84.01 g/mol

3: Divide each element's molar mass by molar mass of NaHCO₃ and multiply it by 100:

For Na:

                 =  22.99 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  27.36 %

For H:

                 =  1.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  1.20 %

For C:

                 =  12.01 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  14.29 % ≈ 14.30 %

For O:

                 =  48.0 g.mol⁻¹ ÷ 84.01 g.mol⁻¹ × 100

                 =  57.13 % ≈ 57.14 %

8 0
3 years ago
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