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<em>Q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em> </em><em>How many km are in 5.6mm? </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>3 </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-6 </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-3 </em>
<em>=</em><em>></em><em> </em><em>5.6x10</em><em>^</em><em>6</em>
<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em>-</em>

<em>E</em><em>x</em><em>p</em><em>l</em><em>a</em><em>n</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em>-</em>
By using the formula-

As 1 with 6 zeros, we convert it into exponential form.

As this above value is fraction type, we can do the reciprocal, thus, the exponent gets a negative value.

Now combine with given question.

Answer:the Boundary of an advancing mass of warm air, in particular the leading edge of the warm sector of a low-pressure system.
Explanation:
Answer:
% of n-propyl chloride = 43.48 %
Explanation:
There are 2 secondary hydrogens and 6 primary hydrogens
The rate of abstraction of seondary hydrogen = 3.9 X rate of abstraction of primary hydrogen
probability of formation of isopropyl chloride = 3.9 X 1 (relative rate X relative number of secondary hydrogens)
Probability of formation of n-propyl chloride = 1 X 3 (relative rate X relative number of primary hydrogens)
Total probability = 3.9
% of n-propyl chloride = 3 X 100 / 6.9 = 43.48 %
Physical<span> changes involve a new </span>form<span> or shape of matter,
</span>
Chemical change<span> is any </span>change<span> that results in the formation of new </span>chemical<span> substances.</span>