Answer:
0.74
Step-by-step explanation:
P(A∪B) = P(A) + P(B) - P(A∩B) = 0.57 + 0.17 - 0
P(A∪B) = 0.74
The probability of A∩B is zero because the classes are mutually exclusive.
Answer:
Positive Coterminal Angles = 60°,780°
Negative Coterminal Angles = -300°, -660°
Step-by-step explanation:
<h3>
Positive Coterminal Angles:</h3>
To find nearest two coterminal angle of 420°:
1) Subtract 360° from 420°:
420°- 360° = 60° (First Positive Coterminal Angle)
2)Add 360° to 420°:
420°+ 360° =780° (Second Positive Coterminal Angle)
<h3>
Negative Coterminal angles:</h3>
To find nearest two negative coterminal angles of 420°. We' lave to take the value below 0.
1) Substract 360° from 420°
420°- 360° = 60°
Which is still a positive value.
2) Again Substract 360° from 60°
60°- 360° = -300° (First Negative Coterminal Angle)
3)Subtract 360° from -300°
-300°- 360° = -660° (Second Negative Coterminal Angle)
Answer:
that will be 768!!!
Step-by-step explanation:
