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4 years ago

Pls answer . its urgent pls an

Mathematics

2 answers:

Savatey [412]4 years ago

8 0

Answer:

Step-by-step explanation:

LiRa [457]4 years ago

3 0

Answer:

option c

Step-by-step explanation:

$\frac{-4}{3} * y = \frac{-3}{4}$

shift -4/3 to the right hand side . when it shifts to other side miltiplication changes to division

y = $\frac{-3}{4} /\frac{-4}{3}$

now do reciprocal

y = $\frac{-3}{4} *\frac{3}{-4}$

y = $\frac{-9}{-16}$

minus and minus gets cancel

y = $\frac{9}{16}$

y = $\frac{(3)^2}{(4)^2}$

y = $(\frac{3}{4})^2$

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A circle has a radius of square root 98 units and is centered at (5.9, 6.7). Write the equation of this circle. Please help!

weqwewe [10]

Given:

Given that the radius of the circle is √98 units.

The circle is centered at the point (5.9, 6.7)

We need to determine the equation of the circle.

Equation of the circle:

The general form of the equation of the circle is given by

$(x-h)^2+(y-k)^2=r^2$

where (h,k) is the center and r is the radius of the circle.

Substituting the center point (h,k) = (5.9, 6.7) and r = √98, we get;

$(x-5.9)^2+(y-6.7)^2=(\sqrt{98})^2$

Simplifying, we get;

$(x-5.9)^2+(y-6.7)^2=98$

Thus, the equation of the circle is $(x-5.9)^2+(y-6.7)^2=98$

4 0

4 years ago

Please help Me I really need the help

Nana76 [90]

Answer:

Step-by-step explanation:

sinice they are similar they have the same angles so 180-118-15=f

so f=47

3 0

4 years ago

3/2 x 4/3 x 5/4… x 2006/2005

Lady_Fox [76]

Answer:

1003

Step-by-step explanation:

The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.

The simplest form of a telescoping product $a_{k} \ = \ \displaystyle\frac{t_{k}}{t_{k+1}}$ , in which the products of n terms is

$a_{1} \ \times \ a_{2} \ \times \ a_{3} \ \times \ \cdots \times \ a_{n-1} \ \times \ a_{n} \ = \ \displaystyle\frac{t_{1}}{t_{2}} \ \times \ \displaystyle\frac{t_{2}}{t_{3}} \ \times \ \displaystyle\frac{t_{3}}{t_{4}} \ \times \ \cdots \ \times \ \displaystyle\frac{t_{n-1}}{t_{n}} \ \times \ \displaystyle\frac{t_{n}}{t_{n+1}} \\ \\ \-\hspace{5.55cm} = \ \displaystyle\frac{t_{1}}{t_{n+1}}.$ .

In this particular case, $t_{1} \ = \ 2$ , $t_{2} \ = \ 3$ , $t_{3} \ = \ 4$ , ..... , in which each term follows a recursive formula of $t_{n+1} \ = \ t_{n} \ + \ 1$ . Therefore,

$\displaystyle\frac{t_{2}}{t_{1}} \times \displaystyle\frac{t_{3}}{t_{2}} \times \displaystyle\frac{t_{4}}{t_{3}} \times \cdots \times \displaystyle\frac{t_{n}}{t_{n-1}} \times \displaystyle\frac{t_{n+1}}{t_{n}} \ = \ \displaystyle\frac{3}{2} \times \displaystyle\frac{4}{3} \times \displaystyle\frac{5}{4} \times \cdots \times \displaystyle\frac{2005}{2004} \times \displaystyle\frac{2006}{2005} \\ \\ \-\hspace{5.95cm} = \ \displaystyle\frac{2006}{2} \\ \\ \-\hspace{5.95cm} = 1003$

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3 years ago

PLEASE HELP! URGENT! I don’t know how to graph this

jekas [21]

graph (-3, 5)

because you would set it equal to 0 so it would be x + 3 = 0 then subtract 3 on both sides to get x = -3

same thing with x-5

set it equal to 0 to get y - 5 = 0 then just add 5 to get y=5

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4 years ago

Write the value of underlined digit 5165874

nlexa [21]

Which is the underlined digit
which number is underlined

3 0

3 years ago