Answer: 0.8(.50)^t/5
Step-by-step explanation:
P(t)= p^0(1+-r)^t
0.8= initial mass
.50= 100/2-> halving
t/5= how many times for every 5 days
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths.
Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday.
Jan - Friday
Feb - Monday
Mar - Monday
Apr - Thursday
May - Saturday
Jun - Tuesday
Jul - Thursday
Aug - Sunday
Sep - Wednesday
Oct - Friday
Nov - Monday
Dec - Wednesday
Now let's count how many times for each weekday, the 13th falls there.
Sunday - 1
Monday - 3
Tuesday - 1
Wednesday - 2
Thursday - 2
Friday - 2
Saturday - 1
The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc.
So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get:
Jan - Friday
Feb - Monday
Mar - Tuesday
Apr - Friday
May - Sunday
Jun - Wednesday
Jul - Friday
Aug - Monday
Sep - Thursday
Oct - Saturday
Nov - Tuesday
Dec - Thursday
And the weekday totals are:
Sunday - 1
Monday - 2
Tuesday - 2
Wednesday - 1
Thursday - 2
Friday - 3
Saturday - 1
And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year.
And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
Answer: $0.55
Step-by-step explanation: you would divide 4.40 by 8 to get the answer which is 0.55
Hope this helps :)
To solve, set an equation:
472=0.8x
Divide both sides by 0.8
472/0.8=0.8x/0.8
x=590
Answer: The original price was $590
30 gallons of red paint & 20 gallons of blue paint
Step-by-step explanation:
The ratio of red to blue paint drops to make purple paint is 3 : 2
Therefore the total number of gallon, in this case, fifty (50) is equivalent to the total of two ratios (which is 3 + 2 5)
If 5 in the ratio = 50; what about 2 & 3
5 = 50
2 = x
After cross multiplication;
5x = 50 * 2
X = 100/5
X = 20
The same for ratio 3
5 = 50
3 = y
5y = 50 * 3
y = 150/5
y = 30
The answer is therefore; 30 gallons of red paint to 20 gallons of blue paint
Learn More:
For more on ratios check out;
brainly.com/question/11662922
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