Answer:
The answer is 60
Step-by-step explanation:
16 x 4 - 4
64 - 4
60
Hope this helped!
Answer:
B) 4
Step-by-step explanation:
There is an outbuilding that has an area of 80 square feet. The rectangle on the blueprint that represents the outbuilding has an area of 20 square inches. If the actual outbuilding has a wall length of 10 feet, what is the length of that wall on the blueprint . A) 3 B) 4 C) 5 D) 6
The length of the wall on the blue print can be calculated as:
20 square feet ÷ 5
= 4 feet
Answer:
26x³ - 12x² + 5x + 7
Step-by-step explanation:
- (2x³ - 3x + 11) - (3x² + 1) x (4 - 8x)
- 2x³ - 3x+11 - (12x² - 24x³ + 4 - 8x)
- 2x³ - 3x + 11 - 12x² + 24x³ - 4 + 8x
- 26x³ + 5x + 7 - 12x²
= 26x³ - 12x² + 5x + 7
Answer:
The mean is 12, The median is 13, The mode is 14, and the range is 8.
The second choice is the correct answer.
Explanation:
- I found the mean by adding up all the numbers and dividing by the number of numbers, or sun divided by count. The sum of the numbers was 132, and the count was 11. I divided 132 by 11 to get 12.
- I listed the numbers in order from least to greatest. The data set was: 7, 8, 10, 12, 12, 13, 13, 14, 14, 14, 15
- I found the median by crossing off the number on each end of the data set, and kept going. For example, I crossed off 8, and then 15, and then 10, and then 14 and so on until I got to the middle number. (Keep in mind, if there are two middle numbers, find the mean of them [add them and divide by two])
- The mode is the number that shows up the most in the data set, so I looked at the data set and saw that 14 showed up 3 times, more times than any other number.
- The range is the difference between the greatest and least number (maximum and minimum) so I just subtracted 15 - 7 to get a difference of 8.
We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>
</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in
the answer is
4.23 in
