Question

LAB: Parsing food data in C++

Answer 1

Answer:

Implementation of the given problem in C++:

#include <bits/stdc++.h>

using namespace std;

int main() {

 vector<string> category, name, description, availability;

 string str;

 cout << "Enter the name of text file to open: ";

 cin >> str;

 ifstream file(str);

 while (getline(file, str)) {

   size_t pos1 = str.find('\t');             // to find the first tab delimiter

   size_t pos2 = str.find('\t', pos1 + 1);   // to find the second tab delimiter

   size_t pos3 = str.find('\t', pos2 + 1);   // to find the third tab delimiter

   category.push_back(str.substr(0, pos1));

   name.push_back(str.substr(pos1 + 1, pos2 - pos1 - 1));

   description.push_back(str.substr(pos2 + 1, pos3 - pos2 - 1));

   availability.push_back(str.substr(pos3 + 1, str.length() - pos3));

 }

 for (int i = 0; i < name.size(); i++)

   if (availability[i] == "Available")

     cout << name[i] << " (" << category[i] << ") -- " << description[i] << endl;

}

Output:-