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vaieri [72.5K]
3 years ago
9

Help Will give crown!!

Mathematics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

the answer is 6

Step-by-step explanation:

if u look 2.5 gives u 3 so 5 would give u 6

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Can you help show me where they belong ? pls help asap
kozerog [31]

y=3x, y=(2/7)x,-0.5=y are all on direct the other ones are on the other side i just did the question they correct. :)

5 0
3 years ago
a 5th grade volleyball team scored 32 points in one game. of those points 2/8 were scored in the second half. how many points we
Degger [83]

Answer:

Number of points scored in the first half of the match is 24 points.

Step-by-step explanation:

Total point scored in the volleyball game = 32

Let us assume the points scored in the first half = m

and the point scored on the second half = 2/8 of (Total points)

= \frac{2}{8}  \times  32  = 8

⇒ The number of points s cored in the second - half  =  8 points

Now, Points in FIRST half+ Points in SECOND  half=  Total Points

⇒ m+ 8 = 32

or, m  = 32 - 8 =  24

⇒ m = 24

Hence, the number of points scored in the first half is 24 points.

4 0
3 years ago
What is the solution of the following system
AleksAgata [21]

Step-by-step explanation:

8x + 14y = 4 ...1

-6x - 7y = -10 ...2

...2 × 2 in 2 sides of the equation

-12x -14y = -20 ...3

...1 + ...3

8x + 14y +(-12x -14y) = 4 +(-20)

8x + 14y - 12x -14y = 4 - 20

-4x = -16

x = (-16)/(-4)

= 4

replace x in ...1 or ...2 you will reserve y value

and answer in the term of (x,y)

4 0
3 years ago
Solve by substitution. Show each step of your work.<br><br> 2x + y = 7<br><br> 3x + 5y = 14
Monica [59]
Alright...simple...showing all steps.. ;)

You have the equations...

2x+y=7
and
3x+5y=14

To be able to even solve for any of the variables...multiply the equations by...2...and..3...

2x+y=7----*3--> 6x+3y=21
and
3x+5y=14-----*2--->6x+10y=28

Thus,

6x+3y=21
-
6x+10y=28

=========

-7y=-7

y=1

Now, plug y back into any of the original equations....we'll use 2x+y=7 in this case....

2x+(1)=7

2x+1=7
      -1  -1

2x=6

x=3

Thus, the point of intersection for these two equations is (3,1)
8 0
3 years ago
A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are
Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0
2 years ago
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