Answer:
A. 44 g
Explanation:
First, you need to write a balanced equation:
CaCO₃ -> CaO + CO₂
Then, you need to find the molar mass of CaCO₃:
Ca = 40.078 amu
C = 12.0107 amu
3O = 47.9982 amu
_________________
100.0869 amu
Then, you calculate the moles of CaCO₃:
100 g ÷ 100.0869 amu = 0.9991 moles
In the balanced equation, we can see that the molar ratio of CaCO₃ and CO₂ is 1 : 1, so moles of CaCO₃ = moles of CO₂.
Now you need to find the molar mass of CO₂:
C = 12.0107 amu
2O = 31.9988 amu
________________
44.0095 amu
Finally, you can calculate the mass of CO₂ produced:
0.9991 moles * 44.0095 amu = 43.9698 g = 44 g
