Question

When calcium carbonate is heated, it

Answer 1

Answer:

A. 44 g

Explanation:

First, you need to write a balanced equation:

CaCO₃ -> CaO + CO₂

Then, you need to find the molar mass of CaCO₃:

Ca = 40.078 amu

C = 12.0107 amu

3O = 47.9982 amu

_________________

100.0869 amu

Then, you calculate the moles of CaCO₃:

100 g ÷ 100.0869 amu = 0.9991 moles

In the balanced equation, we can see that the molar ratio of CaCO₃ and CO₂ is 1 : 1, so moles of CaCO₃ = moles of CO₂.

Now you need to find the molar mass of CO₂:

C = 12.0107 amu

2O = 31.9988 amu

________________

44.0095 amu

Finally, you can calculate the mass of CO₂ produced:

0.9991 moles * 44.0095 amu = 43.9698 g = 44 g