In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.

Mathematics

1 answer:

fomenos3 years ago

5 0

Answer:

Step-by-step explanation:

JKL= ABC, jkl=abc

1.) use law of sines to find k.

$c^{2} =a^{2} +b^{2} -2abCosC$

$c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515$

2.) use law of cosines to find L

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

plug in for b and c: $\frac{860}{sinB} =\frac{1586.225515}{sin126}$

cross multiply: $\frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}$

$sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\$

L=26

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<h3>What is a sample size?</h3>

The sample size is a term used in market research for defining the number of subjects included in a sample size. By sample size, we understand a group of subjects that are selected from the general population and is considered a representative of the real population for that specific study.

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