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Nonamiya [84]
3 years ago
10

Which type of geometry best describes the following statement?

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

answer C

Hyperbolic geometry

The sum of the angles of a hyperbolic triangle is less than 180°.

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12 male birds for every 9 female birds ratio
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4:3

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Assuming you need the integral expressing the volume of E, the easiest setup is to integrate with respect to y first.

This is done with either

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dx\,\mathrm dz
\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_{-2}^2\int_0^{4-x^2-z^2}\mathrm dy\,\mathrm dz\,\mathrm dx

Thanks to symmetry, integrating with respect to either x or z first will be nearly identical.

First, with respect to x:

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dy\,\mathrm dz
\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-z^2}}\mathrm dx\,\mathrm dz\,\mathrm dy

Next, with respec to z:

\displaystyle\iiint_E\mathrm dV=\int_{-2}^2\int_0^4\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dy\,\mathrm dx
\displaystyle\iiint_E\mathrm dV=\int_0^4\int_{-2}^2\int_{-\sqrt{4-y-z^2}}^{\sqrt{4-y-x^2}}\mathrm dz\,\mathrm dx\,\mathrm dy
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What are the given fractions to find 
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0.6 is 10 times as much as what
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.6 divided by 10 is .06 so .6 is 10 times more than .06. Hope this helps!
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