Answer:
a) 1
b) 2
c) 2
Step-by-step explanation:
a) 
means find the output for 
when 
.
b) 
means find the output for 
when 
c) If 
and 
are truly inverses then 
and 
as long as 
satisfies the domains.
So we should be able to conclude that 
with no work.
However, I will also show work.
since 
from part a.
since 
from part b.
Answer:
y = (x - 2)(x + 4)(x - 1)
Step-by-step explanation:
Given the zeros of a function say x = a and x = b, then
The factors are (x - a) and (x - b) and
y = (x - a)(x - b)
Given the zeros are x = 2, x = - 4, x = 1, then
the factors are (x - 2), (x - (- 4)) and (x - 1), that is
(x - 2), (x + 4), (x - 1) , thus
y = (x - 2)(x + 4)(x - 1)
Answer:
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15
x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666
---
answer:
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15
x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666
---
answer:
each class is 1.07 hours
Step-by-step explanation:
3(2)-18=-12
6-18 = -12
-12 = -12
