In ΔJKL, the measure of ∠L=90°, LJ = 2.8 feet, and JK = 9.3 feet. Find the measure of ∠J to the nearest tenth of a degree.
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Answer:
Center: (2,-1)
Radius: 4 units
Step-by-step explanation:
Equation of the circle in standard form is:
The radius of this circle is located at (-g, -f) and its radius is equal to:
The given equation of circle is:
Re-writing this equation in a form similar to the standard equation:
Comparing this equation with standard equation we can say:
g= -2
f = 1
c = -11
So, the center of the circle will be located at (-g, -f) = (2, -1)
And the radius will be =
Thus the radius of the given circle is 4 units.