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zzz [600]
3 years ago
6

Х- 1, 2, 3 ,4

Mathematics
1 answer:
Len [333]3 years ago
4 0
I think it’s C, good luck
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12-0=12 that is the answer

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Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
Classify each polynomial by degree and number of terms (lesson 17.1) z^2-12
zalisa [80]

Answer:

The degree is "2" and the number of term is "2(binomial)"

Step-by-step explanation:

Considering the expression z^2-12

Largest sum of any term is known as the degree.

Now simplify as follows,

z^2-12

So, the degree is 2 because the largest sum of power is known as degree

And the number of terms is two (2) it means it is binomial.

∵ The degree is "2" and the number of term is "2(binomial)"

5 0
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