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Zinaida [17]
3 years ago
11

The following figures were entered on a checking-account record. Add or subtract them to keep the running total correct. Balance

forward $643.72 Check #5734 to Lupe's Market, for food, for $68.29 $ Deposit of $341.80, a paycheck $ Check #5735 to Broadmoor Community Center in the amount of $34.18 $ Check #5736 to Bill Baughman, for plumbing services, for $60.00 $
Mathematics
2 answers:
levacccp [35]3 years ago
8 0

Answer:

Running Total = $823.05

Step-by-step explanation :

When the figures were entered on a checking account record to keep the running total correct :

Balance forward = $643.72  

Check #5734 to Lupe's Market for food = $68.29

A deposit  = $341.80

Check #5735 to Broadmoor Community Center = $34.18

Check #5736 to Bill Baughman for plumbing services = $60.00

Total Transactions :

643.72 - 68.29 + 341.80 - 34.18 - 60 = $823.05

Total balance = $823.05

Veronika [31]3 years ago
7 0

It is given  Balance forward $643.72 in the account.  An amount of $68.29 is given to to Lupe's Market, for food. In the account a Deposit of $341.80 is made.A Cheque of $34.18 is given to Broadmoor Community Center .Charge for for plumbing services, is $60.00 .

Transactions made in the account = $643.72-68.29+341.80-34.18-60.00

Amount left in the account =$823.05.

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1. 15.87%

2.  6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

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P(x > 8.1)

P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

  • Almost all the data lies within three standard deviation from the mean for a normally distributed data.
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  • About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)

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P(x < 6) =0.0228 = 2.28\%

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4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

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84% of newborn babies weigh between 6.7 and 9.5 pounds.

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4 years ago
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