What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?
1 answer:
The equation of circle is:
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)
The formula for distance is:
r = 2
The equation of circle is
(x+2)^2+(y-1)^2=4
I hope that this is the answer that you were looking for and it has helped you.
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)
The formula for distance is:
r = 2
The equation of circle is
(x+2)^2+(y-1)^2=4
I hope that this is the answer that you were looking for and it has helped you.
You might be interested in
Answer:
The axis of symmetry is at
The graph has an x-intercept at
The graph has a vertex at
Step-by-step explanation:
we have
Statements
case 1) The graph has root at and
The statement is False
Because, the roots of the quadratic equation are the values of x when the value of y is equal to zero (x-intercepts)
Observing the graph, the roots are at and
case 2) The axis of symmetry is at
The statement is True
Observing the graph, the vertex is the point
The axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex
so
the equation of the axis of symmetry is
case 3) The graph has an x-intercept at
The statement is True
see procedure case 1)
case 4) The graph has an y-intercept at
The statement is False
Because, the y-intercept is the value of y when the value of x is equal to zero
Observing the graph, the y-intercept is the point
case 5) The graph has a relative minimum at
The statement is False
Because, is a vertical parabola open downward, therefore the vertex is a maximum
The point represent the vertex of the parabola, so is a maximum
case 6) The graph has a vertex at
The statement is True
see the procedure case 5)
see the attached figure to better understand the problem
Rate of change is also knkown as slope which is found by
=slope if you know 2 points/ordered pairs
aos, if x incheases while y decreases then slope is negative
when x increases while y increases then slpe if positive
also, if you can convert to y=mx+b, m=slope
another thing if you have ax+by=c then slope=-a/b
so first one
2x-5y=15
a=2
b=-5
-2/-5=2/5
slope=2/5
positive
next
y=-4x
-4 =slope=negative
x increases while y decreases
negative
x increases while y decreases
negative
so
Positive
Negative
Negative
Negative
A. 6x-3y=12
sloope=-6/-3=2
B. y=5x+b
slope=5
C. (8-2)/(3-1)=6/2=3
sloope=3
D. goes up 4 units and goes right 1 unit, 4/1=4
sloope=4
5 is greates
B is the answer
A. (6-3)/(4-3)=3/1=3
slope=3
B. y=4+6x
slope=6
C.12x+6y=18
slope=-12/6=-2
D. goes down 5 units as it goest 1 uniit to right aka -5./1
slope=-5
greatest is 6
B is answer
the starting value I would guess si when x=1 what is the greats y value
look at each
first one
A. x=1 and =-3
B.y=3x-8
y=3(1)-8
y=3-8
y=-5
C. 8x+4y=16
8(1)+4y=16
8+4y=16
4y=8
y=2
D. at 1 unit to right it is 1 nit up so y=1
greatest is 2 or C
so just subsitute 1 for x since x represents how many teaspoons
y=16(1)560
y=16+560
y=576 caloris for 1 sugar teaspoon
for honey, just read off the graph
for when x=1
y=504
so calores of sugar=576
calories in honey=504
ANSWERS
Postive
Negative
Negative
Negative
B
B
C
sugar=576
honey=504
aos, if x incheases while y decreases then slope is negative
when x increases while y increases then slpe if positive
also, if you can convert to y=mx+b, m=slope
another thing if you have ax+by=c then slope=-a/b
so first one
2x-5y=15
a=2
b=-5
-2/-5=2/5
slope=2/5
positive
next
y=-4x
-4 =slope=negative
x increases while y decreases
negative
x increases while y decreases
negative
so
Positive
Negative
Negative
Negative
A. 6x-3y=12
sloope=-6/-3=2
B. y=5x+b
slope=5
C. (8-2)/(3-1)=6/2=3
sloope=3
D. goes up 4 units and goes right 1 unit, 4/1=4
sloope=4
5 is greates
B is the answer
A. (6-3)/(4-3)=3/1=3
slope=3
B. y=4+6x
slope=6
C.12x+6y=18
slope=-12/6=-2
D. goes down 5 units as it goest 1 uniit to right aka -5./1
slope=-5
greatest is 6
B is answer
the starting value I would guess si when x=1 what is the greats y value
look at each
first one
A. x=1 and =-3
B.y=3x-8
y=3(1)-8
y=3-8
y=-5
C. 8x+4y=16
8(1)+4y=16
8+4y=16
4y=8
y=2
D. at 1 unit to right it is 1 nit up so y=1
greatest is 2 or C
so just subsitute 1 for x since x represents how many teaspoons
y=16(1)560
y=16+560
y=576 caloris for 1 sugar teaspoon
for honey, just read off the graph
for when x=1
y=504
so calores of sugar=576
calories in honey=504
ANSWERS
Postive
Negative
Negative
Negative
B
B
C
sugar=576
honey=504