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storchak [24]
3 years ago
6

What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0
The equation of circle is:
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)

The formula for distance is:
\sqrt{  ( y_{A}-y_{C )^{2} + (x_{A}- x_{C )^{2} }
r = 2

The equation of circle is
(x+2)^2+(y-1)^2=4

I hope that this is the answer that you were looking for and it has helped you.

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Write an equation of a line that passes through the points (1, 7) and (5, 19) . Give the final form in slope intercept form. (Pl
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Answer:

y = 3x + 4

Step-by-step explanation:

slope = (y2 -y1)/(x2 - x1)

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So far what you have is

y = 3x + b                      To solve for b, use either of the two points.

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We should check that with the other  point

x = 5                  Find y

y = 3(5) + 4

y = 15 + 4

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X + 3 1/2 = 10 What is the value of x?
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