What is the general form of the equation of a circle with its center at (-2, 1) and passing through (-4, 1)?
1 answer:
The equation of circle is:
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)
The formula for distance is:
r = 2
The equation of circle is
(x+2)^2+(y-1)^2=4
I hope that this is the answer that you were looking for and it has helped you.
(x-a)^2+(y-b)^2=r^2 where C(a, b) is the center.
In order to find r you have to find the distance between C(-2, 1) and let's say A(-4, 1)
The formula for distance is:
r = 2
The equation of circle is
(x+2)^2+(y-1)^2=4
I hope that this is the answer that you were looking for and it has helped you.
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Answer:
1. x = 2
2. x = -2
3 x = 1
Step-by-step explanation:
Make x the subjects and work from there
